A program to Add numbers divisible by 3 or 5 in C++

Problem - To find the sum of numbers divisible by 3 or 5.

Input-

20

Output-

Numbers divisible by 3 or 5 are given below

3

5

6

9

10

12

15

18

20

The sum of numbers divisible by 3 or 5 is - 98

Program -

#include<iostream>

using namespace std;

int main()

{

    int num;

    cout<<"Enter the number ";

    cin>>num;

    int sum=0;

    cout<<"\nThe numbers divisible by 3 or 5 are given below "<<endl;

    for(int x=0;x<num;x++)

    {

        if(x%3==0)

        {

            cout<<x<<endl;

            sum=sum+x;

        }

        else if(x%5==0)

        {

            cout<<x<<endl;

            sum=sum+x;

        }

    }

    cout<<"\nSum of numbers divisible by 3 or 5 is "<<sum<<endl;

    return 0;

}